[Solved] What will be the output of this code?class Resource: def __enter__(self): print('Enter') return 'resource' def __exit__(self, exc_type, exc_val, exc_tb): print('Exit') with Resource() as r:... | Python

Python - Context Managers

What will be the output of this code?

class Resource:
    def __enter__(self):
        print('Enter')
        return 'resource'
    def __exit__(self, exc_type, exc_val, exc_tb):
        print('Exit')

with Resource() as r:
    print('Using', r)

AUsing resource\nEnter\nExit

BUsing resource\nExit\nEnter

CEnter\nExit\nUsing resource

DEnter\nUsing resource\nExit

Step-by-Step Solution

Solution:

Step 1: Understand the order of with execution
The __enter__ method runs first, printing 'Enter'. Then the block runs, printing 'Using resource'. Finally, __exit__ runs, printing 'Exit'.
Step 2: Match output order with options
Enter\nUsing resource\nExit matches the sequence: Enter, Using resource, Exit.
Final Answer:
Enter Using resource Exit -> Option D
Quick Check:
__enter__ -> block -> __exit__ = B [OK]

Quick Trick: Remember: enter prints first, then block, then exit prints [OK]

Common Mistakes:

Assuming block runs before __enter__
Mixing order of print statements
Ignoring __exit__ call after block

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Step 2: Match output order with options

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