[Solved] Identify the problem in this code snippet:try: file = open('data.txt') except FileNotFoundError: print('File missing') finally: file.close() | Python

Python - Exception Handling Fundamentals

Identify the problem in this code snippet:

try:
    file = open('data.txt')
except FileNotFoundError:
    print('File missing')
finally:
    file.close()

Afile may not be defined if exception occurs

BFileNotFoundError is not a valid exception

Cfinally block cannot be used with try-except

Dfile.close() should be inside except block

Step-by-Step Solution

Solution:

Step 1: Understand variable scope in try-except-finally
If opening the file fails, 'file' is not assigned, so calling file.close() causes an error.
Step 2: Identify the error cause
The finally block runs always, but 'file' may be undefined if exception occurs, causing a NameError.
Final Answer:
file may not be defined if exception occurs -> Option A
Quick Check:
Undefined variable in finally causes error [OK]

Quick Trick: Check variable defined before using in finally [OK]

Common Mistakes:

MISTAKES

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