[Solved] Examine this code snippet:class CustomError(Exception): def __init__(self, msg): self.msg = msg try: raise CustomError('Error occurred') except CustomError as e:... | Python

Python - Custom Exceptions

Examine this code snippet:

class CustomError(Exception):
    def __init__(self, msg):
        self.msg = msg

try:
    raise CustomError('Error occurred')
except CustomError as e:
    print(e)

What issue will arise when running this code?

AThe exception prints an empty message because __str__ is not defined

BThe code raises a syntax error due to incorrect exception raising

CThe exception is not caught because the except block is wrong

DThere is no issue; the code runs and prints the error message

Step-by-Step Solution

Solution:

Step 1: Analyze exception class
The class stores the message in self.msg but does not override __str__.
Step 2: Effect on printing exception
Printing the exception calls __str__, which defaults to the base Exception's method, resulting in an empty message.
Final Answer:
The exception prints an empty message because __str__ is not defined -> Option A
Quick Check:
Override __str__ to display custom messages [OK]

Quick Trick: Override __str__ to show exception messages [OK]

Common Mistakes:

Assuming message prints automatically
Confusing syntax errors with runtime behavior
Believing except block is incorrect

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Examine this code snippet:

Step 1: Analyze exception class

Step 2: Effect on printing exception

Final Answer:

Quick Check:

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