[Solved] What will be the output of this code?class Counter: def __init__(self): self.count = 0 def increment(self): self.count += 1 c = Counter() c.increment() c.increment() print(c.count) | Python

Python - Methods and Behavior Definition

What will be the output of this code?

class Counter:
    def __init__(self):
        self.count = 0
    def increment(self):
        self.count += 1

c = Counter()
c.increment()
c.increment()
print(c.count)

A0

B1

CError

D2

Step-by-Step Solution

Solution:

Step 1: Initial count value
Counter object starts with count = 0.
Step 2: Increment method calls
Each increment call adds 1 to count. Two calls add 2 total.
Step 3: Print final count
Print outputs 2, the updated count value.
Final Answer:
2 -> Option D
Quick Check:
Increment method updates attribute correctly [OK]

Quick Trick: Each method call can change object state incrementally [OK]

Common Mistakes:

Forgetting to call increment method
Assuming count stays 0
Expecting error from += operation

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What will be the output of this code?

Step 1: Initial count value

Step 2: Increment method calls

Step 3: Print final count

Final Answer:

Quick Check:

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