[Solved] What will be the output of this code?class Example: count = 0 def __init__(self): Example.count += 1 @classmethod def get_count(cls): return cls.count obj1 = Example() obj2 = Example() print(Example.... | Python

Python - Class Methods and Static Methods

What will be the output of this code?

class Example:
    count = 0

    def __init__(self):
        Example.count += 1

    @classmethod
    def get_count(cls):
        return cls.count

obj1 = Example()
obj2 = Example()
print(Example.get_count())

A2

B0

C1

DError

Step-by-Step Solution

Solution:

Step 1: Understand the constructor behavior
Each time an Example object is created, the class variable 'count' increases by 1. Two objects are created, so count becomes 2.
Step 2: Understand the class method output
The class method 'get_count' returns the current value of 'count', which is 2 after creating two objects.
Final Answer:
2 -> Option A
Quick Check:
Class variable incremented twice = 2 [OK]

Quick Trick: Class methods access shared data like 'count' [OK]

Common Mistakes:

Thinking count resets per instance
Confusing instance and class variables
Expecting an error due to method call

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What will be the output of this code?

Step 1: Understand the constructor behavior

Step 2: Understand the class method output

Final Answer:

Quick Check:

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