[Solved] What will be the output of the following code? try: print("Start") x = 1 / 1 except ZeroDivisionError: print("Error") else: print("No Error") print("End") | Python

Python - Advanced Exception Handling

What will be the output of the following code?

try:
    print("Start")
    x = 1 / 1
except ZeroDivisionError:
    print("Error")
else:
    print("No Error")
print("End")

AStart\nNo Error\nEnd

BStart\nEnd

CError\nNo Error\nEnd

DStart\nError\nEnd

Step-by-Step Solution

Solution:

Step 1: Analyze try block execution
The code prints "Start" and calculates 1/1 which is 1, no error occurs.
Step 2: Determine which blocks run
Since no error, except block is skipped, else block runs printing "No Error", then "End" prints after.
Final Answer:
Start No Error End -> Option A
Quick Check:
No error means else runs = D [OK]

Quick Trick: If no error, else runs after try [OK]

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