[Solved] What will be the output of this code?def check_age(age): if age < 18: raise ValueError("Too young") return "Access granted" try: print(check_age(16)) except ValueError as e: print(e) | Python

Python - Advanced Exception Handling

What will be the output of this code?

def check_age(age):
    if age < 18:
        raise ValueError("Too young")
    return "Access granted"

try:
    print(check_age(16))
except ValueError as e:
    print(e)

AToo young

BAccess granted

CValueError exception not caught

DNo output

Step-by-Step Solution

Solution:

Step 1: Analyze function behavior with age 16
Since 16 < 18, the function raises a ValueError with message "Too young".
Step 2: Check exception handling in try-except
The exception is caught by the except block, which prints the error message "Too young".
Final Answer:
Too young -> Option A
Quick Check:
Exception message printed = Too young [OK]

Quick Trick: Exception message prints if caught in except [OK]

Common Mistakes:

Assuming function returns 'Access granted'
Thinking exception crashes program
Missing that except prints the error message

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What will be the output of this code?

Step 1: Analyze function behavior with age 16

Step 2: Check exception handling in try-except

Final Answer:

Quick Check:

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