[Solved] What will be the output of the following code? try: print('Start') x = 5 / 0 print('End') except ZeroDivisionError: print('Error caught') print('Done') | Python

Python - Exception Handling Fundamentals

What will be the output of the following code?

try:
    print('Start')
    x = 5 / 0
    print('End')
except ZeroDivisionError:
    print('Error caught')
print('Done')

AStart End Error caught Done

BError caught Done

CStart Done

DStart Error caught Done

Step-by-Step Solution

Solution:

Step 1: Trace code inside try block
It prints 'Start', then tries to divide 5 by 0, which raises ZeroDivisionError before printing 'End'.
Step 2: Handle exception and continue
The except block catches the error and prints 'Error caught'. After that, the program continues and prints 'Done'.
Final Answer:
Start Error caught Done -> Option D
Quick Check:
Exception stops try block, except runs = C [OK]

Quick Trick: Error stops try; except runs; code after try-except runs [OK]

Common Mistakes:

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