[Solved] What will be the output of this code?class X: def __init__(self): print("X init") class Y(X): def __init__(self): super().__init__() print("Y init") obj = Y() | Python

Python - Inheritance and Code Reuse

What will be the output of this code?

class X:
    def __init__(self):
        print("X init")

class Y(X):
    def __init__(self):
        super().__init__()
        print("Y init")

obj = Y()

AY init\nX init

BError: super() not called properly

CX init

DX init\nY init

Step-by-Step Solution

Solution:

Step 1: Follow constructor calls
Y's constructor calls super().__init__() which runs X's constructor printing "X init".
Step 2: Continue Y's constructor
After parent's init, Y prints "Y init".
Final Answer:
X init\nY init -> Option D
Quick Check:
super().__init__() calls parent constructor first [OK]

Quick Trick: super().__init__() runs parent constructor first [OK]

Common Mistakes:

MISTAKES

Expecting child's print before parent's
Thinking super() causes error
Missing parentheses in super call

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More Python Quizzes

What will be the output of this code?

Step 1: Follow constructor calls

Step 2: Continue Y's constructor

Final Answer:

Quick Check:

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