[Solved] What is the output of this code?class Counter: def __init__(self): self.count = 0 def increment(self): self.count += 1 return self.count c = Counter() print(c.increment()) print(c.increment()) | Python

Python - Constructors and Object Initialization

What is the output of this code?

class Counter:
    def __init__(self):
        self.count = 0
    def increment(self):
        self.count += 1
        return self.count
c = Counter()
print(c.increment())
print(c.increment())

A1 2

B0 1

C1 1

D2 3

Step-by-Step Solution

Solution:

Step 1: Understand the initial state and method behavior
When Counter is created, count is 0. Each increment adds 1 and returns the new value.
Step 2: Trace the two calls to increment()
First call: count goes 0 -> 1, returns 1. Second call: count goes 1 -> 2, returns 2.
Final Answer:
1 2 -> Option A
Quick Check:
Increment adds 1 each call [OK]

Quick Trick: Track self.count changes step-by-step [OK]

Common Mistakes:

Assuming count resets each call
Confusing return values
Ignoring self reference updates

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More Python Quizzes

What is the output of this code?

Step 1: Understand the initial state and method behavior

Step 2: Trace the two calls to `increment()`

Final Answer:

Quick Check:

Want More Practice?

What is the output of this code?

Step 1: Understand the initial state and method behavior

Step 2: Trace the two calls to increment()

Final Answer:

Quick Check:

Want More Practice?

Step 2: Trace the two calls to `increment()`