Solution:Step 1: Value of __name__ in imported moduleWhen helper is imported, its __name__ is "helper".Step 2: Value of __name__ in main.pyWhen running main.py directly, its __name__ is "__main__".Step 3: Output linesImporting helper executes its top-level code (defines run()) but skips the if __nam

[Solved] You have two files:# main.py import helper helper.run() print('Main:', __name__) # helper.py def run(): print('Helper:', __name__) if __name__ == '__main__':... | Python

Python - Modules and Code Organization

You have two files:

# main.py
import helper
helper.run()
print('Main:', __name__)

# helper.py
def run():
    print('Helper:', __name__)

if __name__ == '__main__':
    run()

What is the output when running python main.py?

AHelper: __main__ Main: main

BHelper: __main__ Main: __main__

CHelper: helper Main: main

DHelper: helper Main: __main__

Step-by-Step Solution

Solution:

Step 1: Value of __name__ in imported module
When helper is imported, its __name__ is "helper".
Step 2: Value of __name__ in main.py
When running main.py directly, its __name__ is "__main__".
Step 3: Output lines
Importing helper executes its top-level code (defines run()) but skips the if __name__ == '__main__': block since __name__ is 'helper'. Then helper.run() is explicitly called from main.py, printing 'Helper: helper'. Finally, main.py prints 'Main: __main__'.
Final Answer:
Helper: helper Main: __main__ -> Option D
Quick Check:
Imported modules have __name__ as module name [OK]

Quick Trick: Imported modules have __name__ as module name, not '__main__' [OK]

Common Mistakes:

MISTAKES

Assuming helper.py runs its main block on import
Confusing __name__ values in main and imported modules
Expecting helper.run() to run automatically

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More Python Quizzes

You have two files:

Step 1: Value of name in imported module

Step 2: Value of name in main.py

Step 3: Output lines

Final Answer:

Quick Check:

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