[Solved] What will be the output of this code?try: x = 5 / 0 except Exception: print("Error caught") print("Done") | Python

Python - Exception Handling Fundamentals

What will be the output of this code?

try:
    x = 5 / 0
except Exception:
    print("Error caught")
print("Done")

AZeroDivisionError\nDone

BError caught\nDone

CDone

DNo output, program crashes

Step-by-Step Solution

Solution:

Step 1: Identify the error raised
The code tries to divide 5 by 0, which raises a ZeroDivisionError, a subclass of Exception.
Step 2: Check exception handling and output
The except Exception block catches this error and prints "Error caught". Then the program continues and prints "Done".
Final Answer:
Error caught\nDone -> Option B
Quick Check:
ZeroDivisionError caught = prints error message and continues [OK]

Quick Trick: Generic except catches ZeroDivisionError and prints message [OK]

Common Mistakes:

MISTAKES

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