[Solved] Identify the problem in this code:class Parent: def __init__(self): self.value = 5 class Child(Parent): def __init__(self): self.value = 10 obj = Child() print(obj.value) | Python

Python - Inheritance and Code Reuse

Identify the problem in this code:

class Parent:
    def __init__(self):
        self.value = 5

class Child(Parent):
    def __init__(self):
        self.value = 10

obj = Child()
print(obj.value)

AChild's __init__ does not call Parent's __init__, so parent's init is skipped.

BChild class cannot have its own __init__ method.

CParent class __init__ is private and inaccessible.

DValue attribute is not defined in Child class.

Step-by-Step Solution

Solution:

Step 1: Understand constructor overriding
Child defines its own __init__, which replaces Parent's __init__ unless called explicitly.
Step 2: Check attribute value
Child sets value to 10; Parent's value=5 is skipped because Parent's __init__ not called.
Final Answer:
Child's __init__ does not call Parent's __init__, so parent's init is skipped. -> Option A
Quick Check:
Overriding __init__ hides parent's unless super() called [OK]

Quick Trick: Call super().__init__() to run parent constructor [OK]

Common Mistakes:

Assuming parent's __init__ runs automatically
Thinking Child can't have __init__

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More Python Quizzes

Identify the problem in this code:

Step 1: Understand constructor overriding

Step 2: Check attribute value

Final Answer:

Quick Check:

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