[Solved] Identify the error in this iterator implementation:class MyIter: def __init__(self): self.data = [1, 2, 3] self.index = 0 def __iter__(self): return self def __next__(self): if self.index | Python

Python - Magic Methods and Operator Overloading

Identify the error in this iterator implementation:

class MyIter:
    def __init__(self):
        self.data = [1, 2, 3]
        self.index = 0
    def __iter__(self):
        return self
    def __next__(self):
        if self.index <= len(self.data):
            result = self.data[self.index]
            self.index += 1
            return result
        else:
            raise StopIteration

AThe condition should be <code>self.index < len(self.data)</code>

BMissing <code>return self</code> in __iter__

CShould raise <code>StopIteration</code> before returning result

DIndex should start at 1, not 0

Step-by-Step Solution

Solution:

Step 1: Analyze the index condition
Index goes from 0 to len(data)-1. Using <= allows index == len(data), causing IndexError.
Step 2: Correct the condition
Change condition to self.index < len(self.data) to avoid out-of-range access.
Final Answer:
The condition should be self.index < len(self.data) -> Option A
Quick Check:
Index must be less than length to avoid error [OK]

Quick Trick: Use < to avoid index out of range errors [OK]

Common Mistakes:

MISTAKES

Using <= instead of < in index check
Forgetting to return self in __iter__
Starting index at 1 instead of 0

Master "Magic Methods and Operator Overloading" in Python

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More Python Quizzes

Identify the error in this iterator implementation:

Step 1: Analyze the index condition

Step 2: Correct the condition

Final Answer:

Quick Check:

Want More Practice?