[Solved] Given this code, what will be printed?def func(): try: {}['key'] except KeyError as e: try: 1 / 0 except ZeroDivisionError as ze: raise RuntimeError('Runtime problem') from ze try:... | Python

Python - Advanced Exception Handling

Given this code, what will be printed?

def func():
    try:
        {}['key']
    except KeyError as e:
        try:
            1 / 0
        except ZeroDivisionError as ze:
            raise RuntimeError('Runtime problem') from ze

try:
    func()
except Exception as ex:
    print(ex)
    print(ex.__cause__)

A'key' Runtime problem

BRuntime problem division by zero

CKeyError None

DRuntime problem None

Step-by-Step Solution

Solution:

Step 1: Trace func() execution
Accessing key in empty dict raises KeyError, caught but ignored; then 1/0 raises ZeroDivisionError chained to RuntimeError.
Step 2: Outer except prints RuntimeError and its cause
Prints 'Runtime problem' and original 'division by zero' cause.
Final Answer:
Runtime problem division by zero -> Option B
Quick Check:
Nested chaining shows RuntimeError and ZeroDivisionError cause [OK]

Quick Trick: Nested exceptions chain causes through layers [OK]

Common Mistakes:

MISTAKES

Expecting KeyError to be printed
Ignoring nested exception chaining
Assuming cause is None

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Given this code, what will be printed?

Step 1: Trace func() execution

Step 2: Outer except prints RuntimeError and its cause

Final Answer:

Quick Check:

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