[Solved] What will be the output of this code?class Tally: def __init__(self): self.total = 0 def add(self): self.total += 2 def get_total(self): return self.total t = Tally() t.add() t.add() print(t.... | Python

Python - Methods and Behavior Definition

What will be the output of this code?

class Tally:
    def __init__(self):
        self.total = 0
    def add(self):
        self.total += 2
    def get_total(self):
        return self.total

t = Tally()
t.add()
t.add()
print(t.get_total())

A2

BError

C0

D4

Step-by-Step Solution

Solution:

Step 1: Initial value of total is 0
The constructor sets self.total = 0.
Step 2: Each call to add() increases total by 2
Calling add() twice adds 2 + 2 = 4.
Step 3: get_total() returns current total
Returns 4 after two increments.
Final Answer:
4 -> Option D
Quick Check:
Instance variables update correctly with method calls [OK]

Quick Trick: Instance variables update with each method call [OK]

Common Mistakes:

MISTAKES

Assuming add increments by 1 instead of 2
Not calling methods with parentheses
Confusing class and instance variables

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What will be the output of this code?

Step 1: Initial value of total is 0

Step 2: Each call to add() increases total by 2

Step 3: get_total() returns current total

Final Answer:

Quick Check:

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