[Solved] What will be the output of this code snippet?import csv rows = [['id', 'score'], ['1', '85'], ['2', '90']] with open('scores.csv', 'w', newline='') as f: writer = csv.writer(f) writer.... | Python

Python - Structured Data Files

What will be the output of this code snippet?

import csv
rows = [['id', 'score'], ['1', '85'], ['2', '90']]
with open('scores.csv', 'w', newline='') as f:
    writer = csv.writer(f)
    writer.writerows(rows)

with open('scores.csv', 'r') as f:
    reader = csv.reader(f)
    data = list(reader)
print(data)

Aid,score\n1,85\n2,90

B[['id', 'score'], ['1', '85'], ['2', '90']]

C[('id', 'score'), ('1', '85'), ('2', '90')]

DError: writerows() requires a dictionary

Step-by-Step Solution

Solution:

Step 1: Writing multiple rows with writerows()
The writerows() method writes each list inside rows as a CSV row.
Step 2: Reading all rows into a list
Reading back with csv.reader and converting to list returns a list of lists representing rows.
Final Answer:
[['id', 'score'], ['1', '85'], ['2', '90']] -> Option B
Quick Check:
writerows() writes multiple rows; reading returns list of lists [OK]

Quick Trick: writerows() writes multiple rows from a list of lists [OK]

Common Mistakes:

Expecting string output instead of list
Confusing tuples with lists in output
Thinking writerows() needs dictionaries

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What will be the output of this code snippet?

Step 1: Writing multiple rows with writerows()

Step 2: Reading all rows into a list

Final Answer:

Quick Check:

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