Solution:Step 1: Analyze function callCalling safe_divide('10', 2) tries to divide string by int, which raises TypeError.Step 2: Check exception handlingThe except block for TypeError returns 'Invalid input type'.Final Answer:'Invalid input type' -> Option BQuick Check:TypeError caught returns mess

[Solved] Consider this code:def safe_divide(a, b): try: return a / b except ZeroDivisionError: return 'Cannot divide by zero' except TypeError: return 'Invalid input type'What will safe_divide('10', 2) return? | Python

Python - Exception Handling Fundamentals

Consider this code:

def safe_divide(a, b):
    try:
        return a / b
    except ZeroDivisionError:
        return 'Cannot divide by zero'
    except TypeError:
        return 'Invalid input type'

What will safe_divide('10', 2) return?

A'Cannot divide by zero'

B'Invalid input type'

C5.0

DTypeError exception raised

Step-by-Step Solution

Solution:

Step 1: Analyze function call
Calling safe_divide('10', 2) tries to divide string by int, which raises TypeError.
Step 2: Check exception handling
The except block for TypeError returns 'Invalid input type'.
Final Answer:
'Invalid input type' -> Option B
Quick Check:
TypeError caught returns message [OK]

Quick Trick: TypeError occurs when dividing incompatible types [OK]

Common Mistakes:

Expecting division result
Confusing with ZeroDivisionError
Assuming exception is raised uncaught

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Consider this code:

Step 1: Analyze function call

Step 2: Check exception handling

Final Answer:

Quick Check:

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