[Solved] Identify the problem in this code snippet:try: x = 5 / 0 except ValueError: print('Value error caught') | Python

Python - Exception Handling Fundamentals

Identify the problem in this code snippet:

try:
    x = 5 / 0
except ValueError:
    print('Value error caught')

ANo exception will be raised

BWrong exception caught; should catch ZeroDivisionError

CSyntax error in try block

DCode will print 'Value error caught'

Step-by-Step Solution

Solution:

Step 1: Identify the exception raised
Dividing by zero raises ZeroDivisionError, not ValueError.
Step 2: Check except block
The except block catches ValueError, so ZeroDivisionError is not caught and will cause program crash.
Final Answer:
Wrong exception caught; should catch ZeroDivisionError -> Option B
Quick Check:
Catch correct exception type to handle error [OK]

Quick Trick: Match except block to actual exception type [OK]

Common Mistakes:

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