[Solved] What will be the output of this code?try: num = int('abc') except ValueError: print('Value error caught') except TypeError: print('Type error caught') | Python

Python - Exception Handling Fundamentals

What will be the output of this code?

try:
    num = int('abc')
except ValueError:
    print('Value error caught')
except TypeError:
    print('Type error caught')

AValue error caught

BType error caught

CNo output

DProgram crashes with ValueError

Step-by-Step Solution

Solution:

Step 1: Identify the error raised by int('abc')
Trying to convert 'abc' to int raises a ValueError.
Step 2: Match the error with except blocks
The ValueError is caught by the first except block, so it prints 'Value error caught'.
Final Answer:
Value error caught -> Option A
Quick Check:
int('abc') = ValueError caught [OK]

Quick Trick: Match error type to except block to find output [OK]

Common Mistakes:

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