[Solved] What will be the output of this code? try: with open('file.txt', 'r') as f1, open('file2.txt', 'r') as f2: data1 = f1.read() data2 = f2.... What will be the output of this code? | Python

Python - Context Managers

What will be the output of this code?

try:
    with open('file.txt', 'r') as f1, open('file2.txt', 'r') as f2:
        data1 = f1.read()
        data2 = f2.read()
except FileNotFoundError:
    print('File missing')
else:
    print('Files read successfully')

ANo output

BFiles read successfully

CSyntaxError

DFile missing

Step-by-Step Solution

Solution:

Step 1: Understand exception handling with multiple files
If either file is missing, FileNotFoundError is raised and caught.
Step 2: Predict output if files don't exist
Since files likely don't exist, the except block prints 'File missing'.
Final Answer:
File missing -> Option D
Quick Check:
Missing file triggers except block = A [OK]

Quick Trick: Missing file triggers FileNotFoundError catch [OK]

Common Mistakes:

MISTAKES

Assuming files always exist
Expecting else block to run on error
Confusing syntax error with runtime error

Master "Context Managers" in Python

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More Python Quizzes

What will be the output of this code?

Step 1: Understand exception handling with multiple files

Step 2: Predict output if files don't exist

Final Answer:

Quick Check:

Want More Practice?