[Solved] What will be the output of this code?class Test: def __init__(self): self.__value = 10 def change_value(self): self.__value = 20 obj = Test() obj.change_value() print(obj._Test__value) | Python

Python - Encapsulation and Data Protection

What will be the output of this code?

class Test:
    def __init__(self):
        self.__value = 10
    def change_value(self):
        self.__value = 20
obj = Test()
obj.change_value()
print(obj._Test__value)

A20

B10

CAttributeError

DNone

Step-by-Step Solution

Solution:

Step 1: Initialize private attribute
The private attribute __value is set to 10 in the constructor.
Step 2: Modify private attribute inside method
The method change_value() changes __value to 20.
Step 3: Access private attribute using mangled name
Accessing obj._Test__value returns the updated value 20.
Final Answer:
20 -> Option A
Quick Check:
Private attribute updated and accessed via mangled name [OK]

Quick Trick: Private attribute changes reflect when accessed via mangled name [OK]

Common Mistakes:

MISTAKES

Expecting original value 10 after change
Trying to access __value directly causing error
Confusing attribute names

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What will be the output of this code?

Step 1: Initialize private attribute

Step 2: Modify private attribute inside method

Step 3: Access private attribute using mangled name

Final Answer:

Quick Check:

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