Which of the following is the correct syntax to open three files simultaneously using a single with statement?

easy📝 Syntax Q3 of 15

Python - Context Managers

Which of the following is the correct syntax to open three files simultaneously using a single with statement?

Awith open('a.txt') as f1, open('b.txt') as f2, open('c.txt') as f3:

Bwith open('a.txt') as f1; open('b.txt') as f2; open('c.txt') as f3:

Cwith open('a.txt') as f1 and open('b.txt') as f2 and open('c.txt') as f3:

Dwith open('a.txt'), open('b.txt'), open('c.txt') as f1, f2, f3:

Step-by-Step Solution

Solution:

Step 1: Recall correct with syntax for multiple resources
Multiple resources are separated by commas, each with its own as clause.
Step 2: Check each option
with open('a.txt') as f1, open('b.txt') as f2, open('c.txt') as f3: uses commas and separate as for each file, which is correct syntax.
Final Answer:
with open('a.txt') as f1, open('b.txt') as f2, open('c.txt') as f3: -> Option A
Quick Check:
Multiple with resources separated by commas = B [OK]

Quick Trick: Separate resources with commas and use as for each [OK]

Common Mistakes:

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