[Solved] Find the error in this code snippet:def check_number(num): if num < 0: raise 'Negative number error' return 'Number is positive' print(check_number(-5)) | Python

Python - Advanced Exception Handling

Find the error in this code snippet:

def check_number(num):
    if num < 0:
        raise 'Negative number error'
    return 'Number is positive'

print(check_number(-5))

AYou cannot raise a string directly; it must be an Exception type.

BThe raise statement is missing parentheses.

CThe function should return None instead of a string.

DThe if condition should be num > 0.

Step-by-Step Solution

Solution:

Step 1: Check the raise statement
The code tries to raise a string directly, which is not allowed in Python. Only Exception types can be raised.
Step 2: Correct way to raise errors
Use raise ValueError('message') or another Exception class, not a plain string.
Final Answer:
You cannot raise a string directly; it must be an Exception type. -> Option A
Quick Check:
raise must use Exception type, not string [OK]

Quick Trick: Always raise Exception objects, not strings [OK]

Common Mistakes:

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