[Solved] Given this code, what will be the output?class Parent: def process(self): print('Parent start') class Child(Parent): def process(self): print('Child start') super().... | Python

Python - Inheritance and Code Reuse

Given this code, what will be the output?

class Parent:
    def process(self):
        print('Parent start')

class Child(Parent):
    def process(self):
        print('Child start')
        super().process()
        print('Child end')

obj = Child()
obj.process()

AChild start Parent start Child end

BParent start Child start Child end

CChild start Child end Parent start

DError due to super()

Step-by-Step Solution

Solution:

Step 1: Trace the method calls in Child.process()
First prints 'Child start', then calls super().process() which prints 'Parent start', then prints 'Child end'.
Step 2: Determine output order
Output lines are 'Child start', 'Parent start', 'Child end' in that order.
Final Answer:
Child start Parent start Child end -> Option A
Quick Check:
super() runs parent between child's prints = B [OK]

Quick Trick: super() runs parent method exactly where called [OK]

Common Mistakes:

Assuming parent prints first
Expecting error from super()
Mixing print order

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More Python Quizzes

Given this code, what will be the output?

Step 1: Trace the method calls in Child.process()

Step 2: Determine output order

Final Answer:

Quick Check:

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