[Solved] What is wrong with this code?try: x = int('5') except ValueError: print('Value error') else: print('No error') | Python

Python - Exception Handling Fundamentals

What is wrong with this code?

try:
    x = int('5')
except ValueError:
    print('Value error')
else:
    print('No error')

ANo error, code runs and prints 'No error'

BValueError will be raised and caught

CSyntax error due to else block

Delse block should be except block

Step-by-Step Solution

Solution:

Step 1: Analyze int('5')
int('5') converts string '5' to integer 5 without error.
Step 2: Understand try-except-else flow
Since no exception occurs, else block runs printing 'No error'.
Final Answer:
No error, code runs and prints 'No error' -> Option A
Quick Check:
Successful try runs else block [OK]

Quick Trick: else runs only if no exception occurs [OK]

Common Mistakes:

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