[Solved] What will be the output of this code?try: a = [1, 2, 3] print(a[5]) except IndexError: print('Index error caught') | Python

Python - Exception Handling Fundamentals

What will be the output of this code?

try:
    a = [1, 2, 3]
    print(a[5])
except IndexError:
    print('Index error caught')

A3

BKeyError

Cnull

DIndex error caught

Step-by-Step Solution

Solution:

Step 1: Analyze list access
Accessing a[5] is out of range since list has only 3 elements (indices 0-2).
Step 2: Identify exception and handling
This raises IndexError, which is caught by except block printing 'Index error caught'.
Final Answer:
Index error caught -> Option D
Quick Check:
Out of range list index = IndexError caught [OK]

Quick Trick: Out-of-range list access raises IndexError [OK]

Common Mistakes:

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