While–else behavior in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print "Done" after the while loop finishes normally.

Python

count = 0
while count < 3:
    print(count)
    count += 1
else:
    print([1])

Drag options to blanks, or click blank then click option'

Acount

B"Done"

CDone

D"count"

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting quotes around the string in print.

Trying to print the variable count instead of the message.

The else block runs after the while loop finishes normally. Printing the string "Done" shows this.

2fill in blank

medium

Complete the code to break the loop when count reaches 2.

Python

count = 0
while count < 5:
    if count == [1]:
        break
    print(count)
    count += 1
else:
    print("Finished")

Drag options to blanks, or click blank then click option'

A2

B4

C5

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number outside the loop range.

Not breaking the loop at the correct count.

The loop breaks when count equals 2, so the else block will not run.

3fill in blank

hard

Fix the error in the else block to print "Loop ended" only if no break occurs.

Python

i = 0
while i < 4:
    if i == 5:
        break
    print(i)
    i += 1
else:
    print([1])

Drag options to blanks, or click blank then click option'

A"Loop ended"

BLoop ended

Ci

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Printing a variable instead of a string.

Missing quotes causing a NameError.

The else block prints the string "Loop ended" only if the loop finishes without break. The string must be in quotes.

4fill in blank

hard

Fill both blanks to create a dictionary of squares for numbers less than 5, but only if the number is even.

Python

squares = {x: x[1]2 for x in range(5) if x [2] 2 == 0}

Drag options to blanks, or click blank then click option'

A**

B%

C==

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using + instead of ** for squares.

Using == instead of % for checking evenness.

The expression x**2 calculates the square. The condition x % 2 == 0 checks if x is even.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than 1.

Python

result = { [1]: [2] for k, v in data.items() if v [3] 1 }

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using k instead of k.upper() for keys.

Using < instead of > in the condition.

The key is converted to uppercase with k.upper(). The value v is used. The condition v > 1 filters values greater than 1.