Type checking using type() in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check the type of variable x.

Python

x = 10
print(type([1]))

Drag options to blanks, or click blank then click option'

Atype

B10

C'x'

Dx

Attempts:

3 left

💡 Hint

Common Mistakes

Putting the value 10 directly inside type() instead of the variable.

Using quotes around the variable name.

Using type(x) returns the type of the variable x.

2fill in blank

medium

Complete the code to check if y is of type str.

Python

y = 'hello'
if type(y) == [1]:
    print('y is a string')

Drag options to blanks, or click blank then click option'

Aint

Bstr

Cfloat

Dlist

Attempts:

3 left

💡 Hint

Common Mistakes

Using quotes around 'str' which makes it a string literal, not a type.

Comparing to the wrong type like int or float.

The type of a string is str, so we compare type(y) to str.

3fill in blank

hard

Fix the error in the code to correctly check if z is a list.

Python

z = [1, 2, 3]
if type(z) [1]:
    print('z is a list')

Drag options to blanks, or click blank then click option'

Alist

Bstr

C== list

D== str

Attempts:

3 left

💡 Hint

Common Mistakes

Using single equals = instead of double equals ==.

Putting the type inside quotes, making it a string.

The comparison operator should be ==, and the type to compare is list without quotes.

4fill in blank

hard

Fill both blanks to create a dictionary of variable names and their types for a and b.

Python

a = 5
b = 'text'
types = {'a': [1], 'b': [2]
print(types)

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Atype(a)

Btype(b)

Ca

Db

Attempts:

3 left

💡 Hint

Common Mistakes

Putting the variable itself instead of its type.

Mixing up the variables inside type().

Use type(a) and type(b) to get the types of variables a and b.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps each word to its type if the word is a string.

Python

items = [123, 'apple', 4.5]
types_dict = { [1] : [2] for [3] in items if type([3]) == str }
print(types_dict)

Drag options to blanks, or click blank then click option'

Aitem

Btype(item)

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names inconsistently.

Not using type() to get the type.

Use item as the variable name, map it to type(item), and iterate with for item in items.