How can you modify this code to check if val is either a string or a list using type()?

hard📝 Application Q9 of 15

Python - Variables and Dynamic Typing

How can you modify this code to check if val is either a string or a list using type()?

if type(val) == str:
    print("String")

Aif type(val) == str and list:

Bif type(val) == (str, list):

Cif type(val) in ('str', 'list'):

Dif type(val) == str or type(val) == list:

Step-by-Step Solution

Solution:

Step 1: Understand the goal
We want to check if val is either a string or a list.
Step 2: Evaluate options
if type(val) == str or type(val) == list: uses 'or' with two type comparisons correctly. if type(val) == (str, list): incorrectly compares to a tuple. if type(val) in ('str', 'list'): compares to strings incorrectly. if type(val) == str and list: uses 'and' incorrectly.
Final Answer:
if type(val) == str or type(val) == list: -> Option D
Quick Check:
Use 'or' to check multiple types with type() [OK]

Quick Trick: Use 'or' to combine multiple type() checks [OK]

Common Mistakes:

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