[Solved] What is wrong with this code?data = 3.5 if type(data) == 'float': print("Float detected") — Ans: Comparing type to string instead of type object | Python

Python - Variables and Dynamic Typing

What is wrong with this code?

data = 3.5
if type(data) == 'float':
    print("Float detected")

AComparing type to string instead of type object

BMissing colon after if statement

CUsing '==' instead of 'is' for type comparison

DNo error, code works fine

Step-by-Step Solution

Solution:

Step 1: Check the comparison in if condition
The code compares type(data) to the string 'float', which is incorrect.
Step 2: Correct comparison should be to the type object
Use float (without quotes) to compare types, not the string 'float'.
Final Answer:
Comparing type to string instead of type object -> Option A
Quick Check:
Compare type() to type objects, not strings [OK]

Quick Trick: Compare to type objects like float, not strings 'float' [OK]

Common Mistakes:

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