Truthy and falsy values in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if the variable is truthy.

Python

if [1]:
    print("It's truthy!")

Drag options to blanks, or click blank then click option'

ANone

B0

CFalse

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 or None which are falsy and won't enter the if block.

The value 1 is truthy in Python, so the condition passes and prints the message.

2fill in blank

medium

Complete the code to print 'Empty' if the list is falsy (empty).

Python

my_list = []
if not [1]:
    print('Empty')

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Alen(my_list)

Bmy_list

Cmy_list[0]

DTrue

Attempts:

3 left

💡 Hint

Common Mistakes

Using len(my_list) which is 0 but not directly the list variable.

Using my_list[0] which causes an error if list is empty.

An empty list is falsy, so not my_list is True and prints 'Empty'.

3fill in blank

hard

Fix the error in the code to check if the string is falsy.

Python

text = ''
if [1]:
    print('Not empty')
else:
    print('Empty')

Drag options to blanks, or click blank then click option'

Atext

Btext == None

Clen(text) > 0

Dtext is False

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'text' alone works but the question asks to fix the error, so explicit length check is better.

Comparing string to None or False is wrong.

Using len(text) > 0 correctly checks if the string is not empty.

4fill in blank

hard

Fill both blanks to create a dictionary of words with their lengths, only for words longer than 3 characters.

Python

words = ['cat', 'house', 'dog', 'elephant']
lengths = {word: [1] for word in words if [2]

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Alen(word)

Blen(word) > 3

Cword.startswith('e')

Dword == 'dog'

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.startswith('e') filters only words starting with 'e', not length.

Using word == 'dog' filters only 'dog', not length.

The dictionary comprehension uses len(word) for values and filters words with length greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys, values as word lengths, only for words with length greater than 4.

Python

words = ['apple', 'bat', 'carrot', 'dog']
result = { [1]: [2] for w in words if [3] }

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Aw.upper()

Blen(w)

Clen(w) > 4

Dw.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using w.lower() instead of w.upper() for keys.

Filtering words with length less than or equal to 4.

The dictionary comprehension uses uppercase words as keys, their lengths as values, and filters words longer than 4 characters.