[Solved] Identify the bug in this code:items = [0, 1, 2] for item in items: if item: print("Falsy") else: print("Truthy") | Python

Python - Data Types as Values

Identify the bug in this code:

items = [0, 1, 2]
for item in items:
    if item:
        print("Falsy")
    else:
        print("Truthy")

ANo bug, code works correctly

BThe loop should use 'if not item:' instead of 'if item:'

CThe list contains invalid values

DThe print statements are reversed for truthy and falsy

Step-by-Step Solution

Solution:

Step 1: Analyze the condition and prints
The condition 'if item:' is True for non-zero values, but prints "Falsy" which is incorrect.
Step 2: Correct the print statements
When item is truthy, it should print "Truthy", and when falsy, print "Falsy".
Final Answer:
Print statements are reversed -> Option D
Quick Check:
Truthy check must print "Truthy" [OK]

Quick Trick: Match print messages to condition truthiness [OK]

Common Mistakes:

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