[Solved] The following code is intended to print "Falsy" if val is falsy, but it always prints "Truthy". What is the error?val = 0 if val == False: print("Falsy") else: print("Truthy") | Python

Python - Data Types as Values

The following code is intended to print "Falsy" if val is falsy, but it always prints "Truthy". What is the error?

val = 0
if val == False:
    print("Falsy")
else:
    print("Truthy")

AUsing '==' instead of 'is' for comparison

BThe variable 'val' should be converted to bool first

CComparing with False misses some falsy values

DNo error; the code works correctly

Step-by-Step Solution

Solution:

Step 1: Understand comparison with False
Using val == False only matches if val equals exactly False or behaves equal to it. But some falsy values like 0 compare equal to False, so this seems correct here.
Step 2: Check why it prints "Truthy"
Actually, 0 == False is True, so it should print "Falsy". If it prints "Truthy", likely the code is different or the question expects the explanation that comparing with False is not reliable for all falsy values like empty containers or None.
Final Answer:
Comparing with False misses some falsy values -> Option C
Quick Check:
Use 'if not val:' to catch all falsy [OK]

Quick Trick: Use 'if not val:' to catch all falsy values, not '== False' [OK]

Common Mistakes:

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The following code is intended to print "Falsy" if val is falsy, but it always prints "Truthy". What is the error?