String values and text handling in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the string 'Hello, World!'.

Python

print([1])

Drag options to blanks, or click blank then click option'

A'Hello, World!'

BHello, World!

C"Hello World"

DHello World

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to use quotes around the text.

Using quotes inconsistently or missing them.

Strings in Python must be enclosed in quotes to be recognized as text.

2fill in blank

medium

Complete the code to get the length of the string stored in variable text.

Python

length = [1](text)

Drag options to blanks, or click blank then click option'

Acount

Blen

Csize

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using non-existent functions like count or size for length.

Trying to access length as an attribute instead of a function.

The built-in function len() returns the number of characters in a string.

3fill in blank

hard

Fix the error in the code to convert the string to uppercase.

Python

result = text.[1]()

Drag options to blanks, or click blank then click option'

AupperCase

Buppercase

Cupper

DtoUpperCase

Attempts:

3 left

💡 Hint

Common Mistakes

Using JavaScript style method names like toUpperCase.

Capitalizing method names incorrectly.

The correct method to convert a string to uppercase in Python is upper().

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, only for words longer than 3 characters.

Python

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B<

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the wrong comparison operator in the condition.

We use len(word) to get the length and filter words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys, their original form as values, only for words starting with 'a'.

Python

result = {{ [1]: [2] for word in words if word.[3]('a')}

Drag options to blanks, or click blank then click option'

Aword.upper()

Bword

Cstartswith

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lower() instead of upper() for keys.

Using the wrong method name for checking the start of a string.

Use word.upper() for keys, word for values, and startswith('a') to filter words starting with 'a'.

Practice

1. What is the correct way to create a string in Python?

easy

A. Using quotes like "Hello" or 'Hello'

B. Using parentheses like (Hello)

C. Using curly braces like {Hello}

D. Using square brackets like [Hello]

Solution

1. Step 1: Understand string syntax in Python

   Strings are text and must be enclosed in quotes, either single or double.

2. Step 2: Check each option

   Only Using quotes like "Hello" or 'Hello' uses quotes correctly. Parentheses, curly braces, and square brackets are for other data types.

3. Final Answer:

   Using quotes like "Hello" or 'Hello' -> Option A

4. Quick Check:

   Strings need quotes = C [OK]

Hint: Remember: strings always need quotes around text [OK]

Common Mistakes:

• Using parentheses instead of quotes
• Confusing brackets with quotes
• Forgetting to close quotes

2. Which of the following is the correct syntax to create a multi-line string in Python?

easy

A. '''This is a multi-line string'''

B. "This is a multi-line string"

C. 'This is a multi-line string'

D. --This is a multi-line string--

Solution

1. Step 1: Recall multi-line string syntax

   Python uses triple quotes (either ''' or """) to create strings that span multiple lines.

2. Step 2: Evaluate options

   '''This is a multi-line string''' uses triple single quotes correctly. Options B and C use single or double quotes for single-line strings. --This is a multi-line string-- is invalid syntax.

3. Final Answer:

   '''This is a multi-line string''' -> Option A

4. Quick Check:

   Triple quotes = multi-line string [OK]

Hint: Use triple quotes for multi-line strings [OK]

Common Mistakes:

• Using single or double quotes for multi-line text
• Using invalid symbols like --
• Not closing triple quotes properly

3. What will be the output of the following code?

text = "Hello World"
print(text[6:])

medium

A. Hello

B. World

C. World!

D. Hello World

Solution

1. Step 1: Understand string slicing

   text[6:] means start from index 6 to the end of the string. Indexing starts at 0.

2. Step 2: Identify substring from index 6

   In "Hello World", index 6 is 'W', so text[6:] is "World".

3. Final Answer:

   World -> Option B

4. Quick Check:

   text[6:] = World [OK]

Hint: Remember string index starts at 0; slice from index 6 to end [OK]

Common Mistakes:

• Confusing index start point
• Including extra characters like '!'
• Printing entire string instead of slice

4. Find the error in this code snippet:

name = 'Alice
print(name)

medium

A. Incorrect use of newline character

B. print() function is misspelled

C. Missing closing quote for the string

D. Variable name is invalid

Solution

1. Step 1: Check string syntax

   The string starts with a single quote but does not have a closing quote before the newline.

2. Step 2: Identify syntax error

   Because the closing quote is missing, Python will raise a syntax error.

3. Final Answer:

   Missing closing quote for the string -> Option C

4. Quick Check:

   Unclosed string causes syntax error [OK]

Hint: Always close your quotes before newline or end [OK]

Common Mistakes:

• Forgetting to close quotes
• Thinking newline character causes error
• Assuming print is misspelled

5. You have a list of words: words = ['apple', 'banana', 'cherry']. Which code correctly joins them into a single string separated by commas?

hard

A. result = ','.join([words])

B. result = words.join(',')

C. result = ','.join('words')

D. result = ','.join(words)

Solution

1. Step 1: Understand join() method usage

   The join() method is called on the string separator and takes an iterable of strings as argument.

2. Step 2: Check each option

   result = ','.join(words) correctly calls join on the comma string with the list words. Others misuse join or pass wrong arguments.

3. Final Answer:

   result = ','.join(words) -> Option D

4. Quick Check:

   Separator.join(list) joins list items [OK]

Hint: Call join on separator string, pass list to join() [OK]

Common Mistakes:

• Calling join on the list instead of the string
• Passing string 'words' instead of list variable
• Passing list inside another list