String values and text handling in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print the string 'Hello, World!'.

Python

print([1])

Drag options to blanks, or click blank then click option'

A'Hello, World!'

BHello, World!

C"Hello World"

DHello World

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting to use quotes around the text.

Using quotes inconsistently or missing them.

Strings in Python must be enclosed in quotes to be recognized as text.

2fill in blank

medium

Complete the code to get the length of the string stored in variable text.

Python

length = [1](text)

Drag options to blanks, or click blank then click option'

Acount

Blen

Csize

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using non-existent functions like count or size for length.

Trying to access length as an attribute instead of a function.

The built-in function len() returns the number of characters in a string.

3fill in blank

hard

Fix the error in the code to convert the string to uppercase.

Python

result = text.[1]()

Drag options to blanks, or click blank then click option'

AupperCase

Buppercase

Cupper

DtoUpperCase

Attempts:

3 left

💡 Hint

Common Mistakes

Using JavaScript style method names like toUpperCase.

Capitalizing method names incorrectly.

The correct method to convert a string to uppercase in Python is upper().

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, only for words longer than 3 characters.

Python

lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B<

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the wrong comparison operator in the condition.

We use len(word) to get the length and filter words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys, their original form as values, only for words starting with 'a'.

Python

result = {{ [1]: [2] for word in words if word.[3]('a')}

Drag options to blanks, or click blank then click option'

Aword.upper()

Bword

Cstartswith

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lower() instead of upper() for keys.

Using the wrong method name for checking the start of a string.

Use word.upper() for keys, word for values, and startswith('a') to filter words starting with 'a'.