Numeric values (int and float behavior) in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to convert the string '123' to an integer.

Python

num = [1]('123')
print(num)

Drag options to blanks, or click blank then click option'

Afloat

Bstr

Cint

Dbool

Attempts:

3 left

💡 Hint

Common Mistakes

Using float() instead of int() when you want a whole number.

Using str() which keeps the value as text.

The int() function converts a string representing a whole number into an integer type.

2fill in blank

medium

Complete the code to get the decimal number 3.14 from a string.

Python

pi = [1]('3.14')
print(pi)

Drag options to blanks, or click blank then click option'

Aint

Bbool

Cstr

Dfloat

Attempts:

3 left

💡 Hint

Common Mistakes

Using int() which cannot convert decimal strings.

Using str() which keeps the value as text.

The float() function converts a string with decimals into a floating-point number.

3fill in blank

hard

Fix the error in the code to correctly convert the float 7.0 to an integer.

Python

number = 7.0
result = [1](number)
print(result)

Drag options to blanks, or click blank then click option'

Aint

Bfloat

Cstr

Dbool

Attempts:

3 left

💡 Hint

Common Mistakes

Using float() which keeps the decimal.

Using str() which converts to text.

The int() function converts a float to an integer by removing the decimal part.

4fill in blank

hard

Fill both blanks to create a dictionary with numbers as keys and their squares as values, only for numbers greater than 3.

Python

squares = {x: x[1]2 for x in range(1, 6) if x [2] 3}
print(squares)

Drag options to blanks, or click blank then click option'

A**

B>

C<

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using + instead of ** for squaring.

Using < instead of > in the condition.

The ** operator calculates powers, and > filters numbers greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys, values as floats, and only include values greater than 0.

Python

result = [1]: [2] for k, v in data.items() if v [3] 0}}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dfloat(v)

Attempts:

3 left

💡 Hint

Common Mistakes

Using v directly instead of converting to float.

Using < instead of > in the condition.

Not converting keys to uppercase.

Keys are converted to uppercase with k.upper(), values converted to float with float(v), and filtered for values greater than 0 with >.

Practice

1.

Which of the following is an example of a float in Python?

1. 42
2. 3.14
3. -7
4. 0

easy

A. 42

B. 3.14

C. -7

D. 0

Solution

1. Step 1: Understand what a float is

   A float is a number with a decimal point, like 3.14.

2. Step 2: Identify the float among options

   Only 3.14 has a decimal point, so it is a float.

3. Final Answer:

   3.14 -> Option B

4. Quick Check:

   Float = 3.14 [OK]

Hint: Floats always have a decimal point [OK]

Common Mistakes:

• Choosing integers as floats
• Confusing negative numbers with floats
• Ignoring decimal points

2.

Which of the following is the correct way to convert the float 5.7 to an integer in Python?

easy

A. float(5.7)

B. int(5,7)

C. int('5.7')

D. int(5.7)

Solution

1. Step 1: Recall how to convert float to int

   Use the int() function with a float value as argument.

2. Step 2: Check each option

   int(5.7) correctly converts float 5.7 to int 5. int('5.7') causes error, int(5,7) is invalid syntax.

3. Final Answer:

   int(5.7) -> Option D

4. Quick Check:

   int(5.7) = 5 [OK]

Hint: Use int() directly on float to convert [OK]

Common Mistakes:

• Trying int() on string with decimal
• Using wrong syntax like int(5,7)
• Using float() instead of int()

3.

What is the output of the following code?

x = 7 / 2
print(type(x))
print(x)

medium

A. <class 'int'>\n3.5

B. <class 'int'>\n3

C. <class 'float'>\n3.5

D. SyntaxError

Solution

1. Step 1: Understand division operator in Python 3

   Division with / always returns a float, even if numbers divide evenly.

2. Step 2: Evaluate the code

   7 / 2 = 3.5, which is a float. So type(x) is <class 'float'> and x is 3.5.

3. Final Answer:

   <class 'float'>\n3.5 -> Option C

4. Quick Check:

   7 / 2 = 3.5 float [OK]

Hint: Division / always returns float in Python 3 [OK]

Common Mistakes:

• Assuming integer division with /
• Confusing type output format
• Expecting 3 instead of 3.5

4.

Find the error in this code snippet:

num = 4.8
num_int = int(num)
print(num_int + ' is the integer value')

medium

A. Cannot add int and str directly

B. No error, code runs fine

C. Syntax error in print statement

D. Cannot convert float to int

Solution

1. Step 1: Check conversion from float to int

   int(4.8) converts float 4.8 to int 4 without error.

2. Step 2: Check print statement

   Adding int and string directly causes a TypeError in Python.

3. Final Answer:

   Cannot add int and str directly -> Option A

4. Quick Check:

   int + str causes TypeError [OK]

Hint: Convert int to str before adding to string [OK]

Common Mistakes:

• Thinking int() conversion fails
• Ignoring type mismatch in addition
• Assuming print syntax error

5.

You have a list of mixed numbers: nums = [1, 2.5, 3, 4.75, 5]. You want to create a new list with all numbers converted to integers by dropping decimals. Which code correctly does this?

hard

A. new_nums = [int(n) for n in nums]

B. new_nums = [float(n) for n in nums]

C. new_nums = [str(int(n)) for n in nums]

D. new_nums = [round(n) for n in nums]

Solution

1. Step 1: Understand the goal

   We want to convert all numbers to int by dropping decimals, not rounding.

2. Step 2: Evaluate each option

   C uses int() which drops decimals correctly. A converts to string, not int. B converts to float, not int. D rounds numbers, which changes values.

3. Final Answer:

   new_nums = [int(n) for n in nums] -> Option A

4. Quick Check:

   int() drops decimals, list comprehension applies to all [OK]

Hint: Use int() in list comprehension to drop decimals [OK]

Common Mistakes:

• Using round() instead of int()
• Converting to string instead of int
• Using float() which keeps decimals