[Solved] What will this code print?value = 15 if value > 10: if value % 2 == 0: print('Even and >10') else: print('Odd and >10') else: print('10 or less') | Python

Python - Conditional Statements

What will this code print?

value = 15
if value > 10:
    if value % 2 == 0:
        print('Even and >10')
    else:
        print('Odd and >10')
else:
    print('10 or less')

AOdd and >10

BEven and >10

C10 or less

DNo output

Step-by-Step Solution

Solution:

Step 1: Check outer if condition
value is 15, which is greater than 10, so outer if block runs.
Step 2: Check inner if condition
Check if 15 % 2 == 0 (even). 15 % 2 is 1, so false. Inner else runs, printing 'Odd and >10'.
Final Answer:
Odd and >10 -> Option A
Quick Check:
15 > 10 and odd prints 'Odd and >10' [OK]

Quick Trick: Check outer condition first, then inner even/odd [OK]

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