Nested conditional execution in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of nested if-else with numbers

What is the output of this Python code?

Python

x = 10
if x > 5:
    if x < 15:
        print("A")
    else:
        print("B")
else:
    print("C")

A B

B A

C C

D No output

💡 Hint

Check the first condition, then the nested one inside it.

x is 10, which is greater than 5 and less than 15, so the inner if prints 'A'.

❓ Predict Output

intermediate

Nested if-else with strings

What will this code print?

Python

word = "hello"
if len(word) > 3:
    if word[0] == 'h':
        print("Starts with h")
    else:
        print("Long word")
else:
    print("Short word")

A Long word

B Short word

C Error

D Starts with h

💡 Hint

Check the length and first letter of the word.

The word 'hello' has length 5 (>3) and starts with 'h', so it prints 'Starts with h'.

❓ Predict Output

advanced

Nested if-else with multiple conditions

What is the output of this code?

Python

num = 7
if num % 2 == 0:
    if num > 10:
        print("Even and large")
    else:
        print("Even and small")
else:
    if num > 5:
        print("Odd and large")
    else:
        print("Odd and small")

A Odd and large

B Odd and small

C Even and large

D Even and small

💡 Hint

Check if the number is even or odd, then check its size.

7 is odd (not divisible by 2) and greater than 5, so it prints 'Odd and large'.

❓ Predict Output

advanced

Nested if-else with boolean logic

What will this code print?

Python

flag1 = True
flag2 = False
if flag1:
    if flag2:
        print("Both True")
    else:
        print("Only flag1 True")
else:
    print("flag1 is False")

A flag1 is False

B Both True

C Only flag1 True

D No output

💡 Hint

Check the values of flag1 and flag2 carefully.

flag1 is True but flag2 is False, so it prints 'Only flag1 True'.

❓ Predict Output

expert

Nested if-else with variable reassignment

What is the value of variable result after running this code?

Python

x = 3
if x > 0:
    if x % 2 == 0:
        result = "Positive even"
    else:
        result = "Positive odd"
else:
    if x == 0:
        result = "Zero"
    else:
        result = "Negative"

A "Positive odd"

B "Negative"

C "Zero"

D "Positive even"

💡 Hint

Check if x is positive and then if it is even or odd.

x is 3, which is positive and odd, so result is 'Positive odd'.