Iteration using range() in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print numbers from 0 to 4 using a for loop and range().

Python

for i in [1](5):
    print(i)

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Arange

Blist

Ctuple

Dset

Attempts:

3 left

💡 Hint

Common Mistakes

Using list(5) instead of range(5) causes an error.

Using tuple(5) or set(5) is invalid for iteration.

The range(5) function generates numbers from 0 up to 4. Using it in the for loop lets us print these numbers one by one.

2fill in blank

medium

Complete the code to print numbers from 3 to 7 using range().

Python

for num in [1](3, 8):
    print(num)

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Atuple

Blist

Crange

Dset

Attempts:

3 left

💡 Hint

Common Mistakes

Using 7 as the stop value will exclude 7 from the output.

Using list or tuple instead of range causes errors.

range(3, 8) generates numbers starting at 3 up to 7 (8 is excluded). This lets the loop print numbers 3 to 7.

3fill in blank

hard

Fix the error in the code to print even numbers from 2 to 10 using range().

Python

for x in range(2, 11, [1]):
    print(x)

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A2

B1

C3

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Using step 1 prints all numbers, not just even ones.

Using step 3 or 4 skips some even numbers.

The third argument in range is the step. Using 2 steps moves from 2 to 4, 6, 8, 10, printing even numbers.

4fill in blank

hard

Fill both blanks to create a dictionary with numbers from 1 to 5 as keys and their squares as values.

Python

squares = {x: x[1]2 for x in [2](1, 6)}

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A**

B*

Crange

Dlist

Attempts:

3 left

💡 Hint

Common Mistakes

Using * instead of ** calculates double the number, not square.

Using list instead of range causes errors in dictionary comprehension.

Using range(1, 6) generates numbers 1 to 5. The expression x**2 calculates the square of each number. Together, they create the dictionary of squares.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase letters as keys and their positions as values for letters A to E.

Python

letters = [1]: [2] for [3] in range(1, 6)}

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Achr(i + 64)

Bi

Dchr(i)

Attempts:

3 left

💡 Hint

Common Mistakes

Using chr(i) gives wrong letters because ASCII codes start at 65 for 'A'.

Using wrong loop variable name causes errors.

The chr(i + 64) converts numbers 1 to 5 into letters A to E. The key is the letter, and the value is the number i. The loop variable is i.