If statement execution flow in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print 'Yes' if the number is greater than 10.

Python

number = 15
if number [1] 10:
    print("Yes")

Drag options to blanks, or click blank then click option'

A>

B<

C!=

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check the wrong condition.

Using '==' checks equality, not greater than.

The condition should check if number is greater than 10, so we use the > operator.

2fill in blank

medium

Complete the code to print 'Even' if the number is divisible by 2.

Python

number = 8
if number [1] 2 == 0:
    print("Even")

Drag options to blanks, or click blank then click option'

A%

B//

C**

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using '//' gives the quotient, not the remainder.

Using '**' is for powers, not division.

The modulo operator % gives the remainder. If number % 2 == 0, the number is even.

3fill in blank

hard

Fix the error in the if statement to correctly check if x is not equal to 5.

Python

x = 7
if x [1] 5:
    print("Not five")

Drag options to blanks, or click blank then click option'

A==

B!=

C=

D<>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '!=' causes a syntax error.

Using '<>' is not supported in Python 3.

The operator != means 'not equal to'. Using = is assignment, which causes an error here.

4fill in blank

hard

Fill both blanks to create a dictionary of words and their lengths, but only for words longer than 3 letters.

Python

words = ["apple", "cat", "banana", "dog"]
lengths = {word: [1] for word in words if len(word) [2] 3}

Drag options to blanks, or click blank then click option'

Alen(word)

B<=

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<=' includes words with length 3 or less.

Using 'word' instead of 'len(word)' gives the word itself, not its length.

We want the length of each word as the value, so use len(word). The condition should check if length is greater than 3, so use >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only if the value is positive.

Python

data = {"a": 1, "b": -2, "c": 3}
result = [1]: [2] for k, v in data.items() if v [3] 0}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'k' instead of 'k.upper()' keeps keys lowercase.

Using '<' instead of '>' filters wrong values.

Keys should be uppercase, so use k.upper(). Values are v. The condition checks if v is greater than 0, so use >.