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Why Identity operators (is, is not) in Python? - Purpose & Use Cases

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The Big Idea

What if two things look the same but are actually different inside? Identity operators reveal the truth!

The Scenario

Imagine you have two boxes that look the same and contain the same toys. You want to check if they are actually the same box or just two boxes with identical toys.

The Problem

Manually checking if two things are the exact same object can be confusing and slow. You might compare their contents and think they are the same, but they could be different objects. This can cause bugs and mistakes in your program.

The Solution

Identity operators is and is not let you quickly and clearly check if two variables point to the exact same object in memory, not just if they look alike.

Before vs After
Before
if a == b:
    print('They look the same')
else:
    print('They are different')
After
if a is b:
    print('They are the same object')
else:
    print('They are different objects')
What It Enables

This lets you write clearer, faster code that knows when two things are truly the same object, avoiding hidden bugs.

Real Life Example

When checking if a variable is None, using is None ensures you are testing identity, not just equality, which is the safest and most reliable way.

Key Takeaways

Identity operators check if two variables point to the exact same object.

They help avoid confusion between objects that look alike but are different.

Using is and is not makes your code clearer and safer.

Practice

(1/5)
1. What does the is operator check in Python?
easy
A. If two variables are of the same type
B. If two variables have the same value
C. If two variables point to the same object
D. If two variables are both numbers

Solution

  1. Step 1: Understand the is operator

    The is operator checks whether two variables refer to the exact same object in memory.
  2. Step 2: Differentiate from equality

    Unlike ==, which checks if values are equal, is checks identity, meaning the same object.
  3. Final Answer:

    If two variables point to the same object -> Option C
  4. Quick Check:

    is checks object identity = C [OK]
Hint: Remember: is means same object, not just equal value [OK]
Common Mistakes:
  • Confusing is with ==
  • Thinking is checks value equality
  • Assuming is works like type comparison
2. Which of the following is the correct syntax to check if variable a is not the same object as b?
easy
A. a != b
B. a is not b
C. a not is b
D. a !== b

Solution

  1. Step 1: Identify the correct identity operator

    The operator to check if two variables are not the same object is is not.
  2. Step 2: Check syntax correctness

    a is not b is the correct syntax; other options are either value comparison or invalid syntax.
  3. Final Answer:

    a is not b -> Option B
  4. Quick Check:

    Correct syntax for identity not equal = D [OK]
Hint: Use is not to check different objects, not != [OK]
Common Mistakes:
  • Using != instead of is not
  • Writing not is which is invalid
  • Using JavaScript style !== in Python
3. What will be the output of this code?
list1 = [1, 2, 3]
list2 = list1
list3 = [1, 2, 3]
print(list1 is list2)
print(list1 is list3)
medium
A. True\nFalse
B. True\nTrue
C. False\nTrue
D. False\nFalse

Solution

  1. Step 1: Analyze list1 is list2

    Since list2 = list1, both point to the same object, so this is True.
  2. Step 2: Analyze list1 is list3

    list3 is a new list with the same values but a different object, so this is False.
  3. Final Answer:

    True\nFalse -> Option A
  4. Quick Check:

    Same object check = True, different object = False [OK]
Hint: Same variable means is True; identical values but new object means False [OK]
Common Mistakes:
  • Assuming identical lists are the same object
  • Confusing is with ==
  • Ignoring that assignment copies reference, not value
4. Find the error in this code snippet:
a = None
if a is not None:
    print("Value exists")
else
    print("No value")
medium
A. Missing colon after else
B. Wrong use of is not
C. None should be in quotes
D. Indentation error

Solution

  1. Step 1: Check syntax of if-else statement

    The else line is missing a colon at the end, which is required in Python.
  2. Step 2: Verify other parts

    The use of is not with None is correct, and None is a keyword, so no quotes needed. Indentation looks fine.
  3. Final Answer:

    Missing colon after else -> Option A
  4. Quick Check:

    Colon needed after else = A [OK]
Hint: Always put a colon after else in Python [OK]
Common Mistakes:
  • Forgetting colon after else
  • Using quotes around None
  • Misusing is not operator
5. You want to check if a variable x is exactly None before processing it. Which is the best way to do this?
hard
A. if x is not None:
B. if x == None:
C. if x != None:
D. if x is None:

Solution

  1. Step 1: Understand the difference between == and is for None

    None is a singleton object in Python. The recommended way to check for it is using is because it checks identity.
  2. Step 2: Choose the correct condition for checking if x is None

    if x is None: correctly checks if x points to the None object.
  3. Final Answer:

    if x is None: -> Option D
  4. Quick Check:

    Use is None to check for None [OK]
Hint: Always use is None to check for None [OK]
Common Mistakes:
  • Using == None instead of is None
  • Using is not None when checking for None
  • Confusing identity with equality for None