Elif ladder execution in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of elif ladder with multiple conditions

What is the output of this Python code?

Python

x = 15
if x < 10:
    print("Less than 10")
elif x < 20:
    print("Between 10 and 19")
elif x < 30:
    print("Between 20 and 29")
else:
    print("30 or more")

A 30 or more

B Less than 10

C Between 20 and 29

D Between 10 and 19

💡 Hint

Check which condition is true first in the elif ladder.

The variable x is 15. The first if condition (x < 10) is false. The first elif (x < 20) is true, so it prints 'Between 10 and 19' and skips the rest.

❓ Predict Output

intermediate

Elif ladder with overlapping conditions

What will this code print?

Python

score = 75
if score >= 90:
    print("Grade A")
elif score >= 80:
    print("Grade B")
elif score >= 70:
    print("Grade C")
else:
    print("Grade F")

A Grade A

B Grade C

C Grade B

D Grade F

💡 Hint

Check conditions from top to bottom and stop at the first true one.

score is 75. The first two conditions are false. The third condition (score >= 70) is true, so it prints 'Grade C'.

❓ Predict Output

advanced

Elif ladder with nested conditions

What is the output of this code?

Python

num = 0
if num > 0:
    if num % 2 == 0:
        print("Positive even")
    else:
        print("Positive odd")
elif num == 0:
    print("Zero")
else:
    print("Negative")

A Zero

B Positive even

C Positive odd

D Negative

💡 Hint

Check the first condition and then the elif condition.

num is 0. The first if (num > 0) is false, so it checks elif (num == 0) which is true, so it prints 'Zero'.

❓ Predict Output

advanced

Elif ladder with boolean expressions

What will this code print?

Python

a = True
b = False
if a and b:
    print("Both True")
elif a or b:
    print("One True")
else:
    print("None True")

A None True

B Both True

C One True

D SyntaxError

💡 Hint

Evaluate the boolean expressions carefully.

a is True and b is False. The first condition (a and b) is False. The second condition (a or b) is True, so it prints 'One True'.

❓ Predict Output

expert

Elif ladder with variable reassignment inside conditions

What is the output of this code?

Python

x = 5
if x > 10:
    x = x + 10
    print(x)
elif x > 3:
    x = x * 2
    print(x)
else:
    x = x - 1
    print(x)
print(x)

A

10
10

B

10
15

C

10
5

D

10
20

💡 Hint

Check how x changes inside the elif block and then the final print.

x is 5. The first if (x > 10) is false. The elif (x > 3) is true, so x becomes 5*2=10 and prints 10. Then the last print prints the updated x which is 10.

Practice

1.

What does an elif ladder do in Python?

easy

A. Only checks the last condition in the ladder

B. Runs all conditions regardless of their truth value

C. Checks multiple conditions in order and runs the first true block

D. Skips all conditions and runs the else block always

Solution

1. Step 1: Understand the purpose of elif ladder

   An elif ladder checks conditions one by one in order.

2. Step 2: Identify behavior on true condition

   It stops checking further once it finds the first true condition and runs that block.

3. Final Answer:

   Checks multiple conditions in order and runs the first true block -> Option C

4. Quick Check:

   Elif ladder = first true condition runs [OK]

Hint: Elif stops at first true condition found [OK]

Common Mistakes:

• Thinking all conditions run
• Believing else runs before elif
• Assuming elif checks last only

2.

Which of these is the correct syntax for an elif statement in Python?

if x > 10:
    print("Big")
____ x > 5:
    print("Medium")
else:
    print("Small")

easy

A. elif

B. else if

C. elseif

D. elif:

Solution

1. Step 1: Recall Python elif syntax

   Python uses 'elif' without spaces or colon after it.

2. Step 2: Check options for correct keyword

   Only 'elif' is correct; 'else if' and 'elseif' are invalid in Python.

3. Final Answer:

   elif -> Option A

4. Quick Check:

   Python elif keyword = elif [OK]

Hint: Use 'elif' exactly, no spaces or colon after it [OK]

Common Mistakes:

• Writing 'else if' like other languages
• Adding colon after elif keyword
• Using 'elseif' as one word

3.

What will be the output of this code?

score = 75
if score >= 90:
    print("A")
elif score >= 80:
    print("B")
elif score >= 70:
    print("C")
else:
    print("F")

medium

A. A

B. B

C. F

D. C

Solution

1. Step 1: Check conditions in order with score=75

   score >= 90? No. score >= 80? No. score >= 70? Yes.

2. Step 2: Print output for first true condition

   Prints "C" and stops checking further.

3. Final Answer:

   C -> Option D

4. Quick Check:

   75 >= 70 = True, prints C [OK]

Hint: Check conditions top to bottom, stop at first true [OK]

Common Mistakes:

• Choosing B or A ignoring order
• Thinking else runs when elif true
• Confusing >= with >

4.

Find the error in this elif ladder code:

num = 10
if num < 5:
    print("Small")
elif num > 5
    print("Big")
else:
    print("Medium")

medium

A. Missing colon after elif condition

B. Wrong indentation of print statements

C. Using else without condition

D. Using < instead of > in if

Solution

1. Step 1: Check syntax of elif line

   Line 'elif num > 5' is missing a colon at the end.

2. Step 2: Identify correct syntax for elif

   Elif condition must end with a colon ':' to be valid.

3. Final Answer:

   Missing colon after elif condition -> Option A

4. Quick Check:

   Elif line needs colon ':' [OK]

Hint: Always put colon after if/elif/else lines [OK]

Common Mistakes:

• Forgetting colon after elif
• Misaligning indentation
• Thinking else needs condition

5.

Given this code, what will be printed if value = 0?

value = 0
if value:
    print("True")
elif value == 0:
    print("Zero")
else:
    print("False")

hard

A. True

B. Zero

C. False

D. No output

Solution

1. Step 1: Evaluate if condition with value=0

   In Python, 0 is treated as False, so 'if value:' is False.

2. Step 2: Check elif condition

   'elif value == 0:' is True, so it prints "Zero" and stops.

3. Final Answer:

   Zero -> Option B

4. Quick Check:

   0 is falsy, elif value==0 True [OK]

Hint: Remember 0 is False, check explicit elif next [OK]

Common Mistakes:

• Thinking if value: is True for 0
• Ignoring elif condition
• Assuming else runs always