Continue statement behavior in Python - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the continue statement do inside a loop?

It skips the rest of the current loop cycle and immediately starts the next iteration of the loop.

beginner

In which types of loops can you use the continue statement?

You can use continue in both for loops and while loops.

intermediate

What happens if continue is used inside a nested loop?

It only affects the innermost loop where it is used, skipping to the next iteration of that loop.

beginner

Consider this code snippet:

for i in range(5):
    if i == 2:
        continue
    print(i)

What will be the output?

The output will be:
0
1
3
4
The number 2 is skipped because continue skips printing when i == 2.

intermediate

Why might you use continue instead of if-else inside a loop?

Using continue can make the code cleaner by avoiding nested if-else blocks and clearly skipping unwanted cases.

What does the continue statement do in a loop?

A Skips the rest of the current iteration and starts the next iteration

B Stops the entire loop immediately

C Exits the current function

D Repeats the current iteration

The continue statement skips the rest of the current loop cycle and moves to the next iteration.

In which loop types can continue be used?

A Only in <code>while</code> loops

B In both <code>for</code> and <code>while</code> loops

C Only in <code>for</code> loops

D Only in <code>if</code> statements

continue works in both for and while loops.

What happens if continue is used inside nested loops?

A It skips the rest of the innermost loop's current iteration

B It skips the rest of all loops

C It exits all loops immediately

D It restarts the outer loop

continue affects only the innermost loop where it is used.

Given this code:

for i in range(3):
    if i == 1:
        continue
    print(i)

What is printed?

A Nothing

B 1 2

C 0 1 2

D 0 2

When i == 1, continue skips printing, so only 0 and 2 are printed.

Why might continue improve code clarity?

A It makes loops run faster

B It replaces all <code>if</code> statements

C It avoids nested <code>if-else</code> blocks by skipping unwanted cases

D It stops the program

continue helps avoid deep nesting by skipping to the next loop iteration early.

Explain how the continue statement changes the flow inside a loop.

Think about what happens when the loop sees <code>continue</code>.

Describe a situation where using continue makes your loop code easier to read.

Consider how skipping some steps early can reduce indentation.

Practice

1. What does the continue statement do inside a loop in Python?

easy

A. Exits the current function

B. Stops the entire loop immediately

C. Skips the rest of the current loop iteration and moves to the next one

D. Repeats the current iteration without moving forward

Solution

1. Step 1: Understand the role of continue

   The continue statement tells the loop to skip the remaining code in the current iteration.

2. Step 2: Identify the loop behavior after continue

   After skipping, the loop moves to the next iteration without stopping the whole loop.

3. Final Answer:

   Skips the rest of the current loop iteration and moves to the next one -> Option C

4. Quick Check:

   continue skips current step [OK]

Hint: Remember: continue skips current step, break stops loop [OK]

Common Mistakes:

• Confusing continue with break
• Thinking continue exits the function
• Assuming continue repeats the iteration

2. Which of the following is the correct syntax to use continue inside a for loop?

easy

A. for i in range(5) { continue }

B. for i in range(5): continue

C. for i in range(5) continue

D. for i in range(5):
continue

Solution

1. Step 1: Check Python loop syntax

   Python requires a colon after the for statement and indentation for the loop body.

2. Step 2: Identify correct placement of continue

   continue must be inside the loop body, properly indented on the next line.

3. Final Answer:

   for i in range(5):\n continue -> Option D

4. Quick Check:

   Colon + indent + continue line [OK]

Hint: Use colon and indent for loop body with continue [OK]

Common Mistakes:

• Missing colon after for statement
• Writing continue on same line without colon
• Using braces {} which are not Python syntax

3. What is the output of this code?

for i in range(5):
    if i == 2:
        continue
    print(i)

medium

A. 0 1 3 4

B. 0 1 2 3 4

C. 2

D. 0 1

Solution

1. Step 1: Trace loop iterations and condition

   The loop runs i from 0 to 4. When i is 2, continue skips printing.

2. Step 2: List printed values

   Values printed are 0, 1, 3, and 4 because 2 is skipped.

3. Final Answer:

   0 1 3 4 -> Option A

4. Quick Check:

   continue skips i=2 print [OK]

Hint: Skip printing when continue triggers, others print [OK]

Common Mistakes:

• Including 2 in output
• Thinking continue stops loop
• Confusing continue with break

4. Find the error in this code snippet:

i = 0
while i < 5:
    if i == 3:
        continue
    print(i)
    i += 1

medium

A. Infinite loop because i is not incremented when i == 3

B. SyntaxError due to missing colon

C. Prints numbers 0 to 4 correctly

D. TypeError because of continue in while loop

Solution

1. Step 1: Analyze loop and continue effect

   When i equals 3, continue skips the rest, so i += 1 is not executed.

2. Step 2: Understand consequence

   Since i stays 3 forever, the loop never ends, causing an infinite loop.

3. Final Answer:

   Infinite loop because i is not incremented when i == 3 -> Option A

4. Quick Check:

   continue skips i++ causes infinite loop [OK]

Hint: Increment loop variable before continue or use else [OK]

Common Mistakes:

• Ignoring that continue skips increment
• Thinking continue causes syntax error
• Assuming loop ends normally

5. You want to print all numbers from 1 to 10 except multiples of 3 using a for loop and continue. Which code correctly does this?

hard

A. for i in range(1, 11):
if i % 3 == 0:
pass
else:
print(i)

B. for i in range(1, 11):
if i % 3 == 0:
continue
print(i)

C. for i in range(1, 11):
if i % 3 == 0:
break
print(i)

D. for i in range(1, 11):
if i % 3 != 0:
continue
print(i)

Solution

1. Step 1: Understand the goal

   We want to skip printing numbers divisible by 3, so use continue when i % 3 == 0.

2. Step 2: Check each option

   for i in range(1, 11): if i % 3 == 0: continue print(i) skips multiples of 3 correctly and prints others. for i in range(1, 11): if i % 3 != 0: continue print(i) skips non-multiples wrongly. for i in range(1, 11): if i % 3 == 0: break print(i) breaks loop early. for i in range(1, 11): if i % 3 == 0: pass else: print(i) uses pass but prints all except multiples of 3 correctly but without continue.

3. Final Answer:

   for i in range(1, 11): if i % 3 == 0: continue print(i) -> Option B

4. Quick Check:

   continue skips multiples of 3 print others [OK]

Hint: Use continue to skip unwanted cases inside loop [OK]

Common Mistakes:

• Using break instead of continue
• Reversing condition logic
• Not skipping multiples of 3