Comparison operators in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of chained comparison

What is the output of this Python code?

Python

x = 5
result = 3 < x <= 5
print(result)

A True

B TypeError

C SyntaxError

D False

💡 Hint

Remember that chained comparisons check all parts together.

The expression 3 < x <= 5 checks if x is greater than 3 and less than or equal to 5. Since x is 5, both conditions are true, so the result is True.

❓ Predict Output

intermediate

Output of equality and identity

What is the output of this code snippet?

Python

a = [1, 2, 3]
b = a
c = a[:]
print(a == b, a is b, a == c, a is c)

A False False False False

B True False True False

C False True False True

D True True True False

💡 Hint

Remember that '==' checks value equality, 'is' checks if two variables point to the same object.

a and b point to the same list, so a is b is True. a and c have the same contents but are different objects, so a == c is True but a is c is False.

❓ Predict Output

advanced

Output of mixed type comparison

What happens when you run this code?

Python

print(5 < '10')

A False

B TypeError

C SyntaxError

D True

💡 Hint

Think about comparing different data types in Python 3.

In Python 3, comparing int and str with < raises a TypeError because these types cannot be ordered.

❓ Predict Output

advanced

Output of complex boolean comparison

What is the output of this code?

Python

x = 10
y = 20
print(x < y and y < 30 or x > 15)

A SyntaxError

B False

C True

D TypeError

💡 Hint

Remember the order of operations for 'and' and 'or'.

x < y is True, y < 30 is True, so 'x < y and y < 30' is True. The 'or x > 15' part is False, but True or False is True.

❓ Predict Output

expert

Output of comparison with custom class

What is the output of this code?

Python

class Number:
    def __init__(self, value):
        self.value = value
    def __lt__(self, other):
        return self.value > other.value

n1 = Number(5)
n2 = Number(3)
print(n1 < n2)

A True

B False

C TypeError

D AttributeError

💡 Hint

Look carefully at the __lt__ method implementation.

The __lt__ method is reversed: it returns True if self.value is greater than other.value. Since 5 > 3, n1 < n2 returns True.