Reading file content (Get-Content) in PowerShell - Practice Problems & Coding Challenges

Challenge - 5 Problems

💻 Command Output

intermediate

What is the output of this PowerShell command?

Given a file named example.txt containing the lines:

Hello
World

What will be the output of this command?

Get-Content example.txt

PowerShell

Get-Content example.txt

A Error: File not found

B Hello World

C System.Object[]

D Hello`nWorld

💡 Hint

Get-Content reads each line as a separate string and outputs them line by line.

Get-Content outputs each line as a separate string, so the output will be two lines: 'Hello' and 'World'.

💻 Command Output

intermediate

What does this command output when reading a file with empty lines?

Assume data.txt contains:

Line1



Line3

What is the output of:

Get-Content data.txt

PowerShell

Get-Content data.txt

A Line1`n`nLine3

B Line1`nLine3

C Line1 Line3

D Error: Empty lines not allowed

💡 Hint

Get-Content preserves empty lines as empty strings in the output.

Empty lines in the file are read as empty strings, so the output includes a blank line between Line1 and Line3.

📝 Syntax

advanced

Which command correctly reads the first 3 lines of a file?

You want to read only the first 3 lines of log.txt. Which command does this correctly?

A Get-Content log.txt -First 3

B Get-Content log.txt | Select-Object -First 3

C Get-Content log.txt -TotalCount 3

D Get-Content log.txt | Where-Object { $_ -le 3 }

💡 Hint

Look for the parameter that limits the number of lines read directly.

The -TotalCount parameter tells Get-Content to read only the specified number of lines from the start.

🔧 Debug

advanced

Why does this command fail with an error?

You run:

Get-Content -Path

and get an error. Why?

PowerShell

Get-Content -Path

A Because the -Path parameter requires a value specifying the file path.

B Because Get-Content does not have a -Path parameter.

C Because the file is empty.

D Because the command needs -TotalCount parameter.

💡 Hint

Check if all required parameters have values.

The -Path parameter needs a file path value; omitting it causes an error.

🚀 Application

expert

How to read a file and output only lines containing 'error' (case-insensitive)?

You want to read server.log and output only lines that contain the word 'error', ignoring case. Which command achieves this?

A Get-Content server.log | Select-String 'error' -CaseSensitive

B Get-Content server.log | Select-String 'error' -SimpleMatch

C Get-Content server.log | Where-Object { $_ -imatch 'error' }

D Get-Content server.log | Where-Object { $_ -match 'error' }

💡 Hint

Look for the operator that matches text ignoring case.

The '-imatch' operator performs a case-insensitive regex match, filtering lines containing 'error' regardless of case.

Practice

1. What does the PowerShell command Get-Content do?

easy

A. Copies a file to a new location

B. Deletes a file from the system

C. Reads the content of a file line by line

D. Creates a new file with specified content

Solution

1. Step 1: Understand the purpose of Get-Content

   The Get-Content cmdlet is designed to read the contents of a file, typically line by line.

2. Step 2: Compare with other file commands

   Deleting, creating, or copying files are done by other cmdlets like Remove-Item, Set-Content, or Copy-Item.

3. Final Answer:

   Reads the content of a file line by line -> Option C

4. Quick Check:

   Get-Content = Read file lines [OK]

Hint: Get-Content always reads file text line by line [OK]

Common Mistakes:

• Confusing Get-Content with file deletion commands
• Thinking it writes or creates files
• Assuming it copies files

2. Which of the following is the correct syntax to read all lines from a file named log.txt using PowerShell?

easy

A. Get-Content -Path log.txt

B. Get-Content log.txt -ReadAll

C. Read-File log.txt

D. Get-FileContent log.txt

Solution

1. Step 1: Recall the correct cmdlet and syntax

   The correct cmdlet to read file content is Get-Content with the -Path parameter specifying the file.

2. Step 2: Evaluate the options

   Get-Content -Path log.txt uses correct syntax. Options A, C, and D use incorrect cmdlets or parameters that do not exist.

3. Final Answer:

   Get-Content -Path log.txt -> Option A

4. Quick Check:

   Correct cmdlet and parameter = Get-Content -Path log.txt [OK]

Hint: Use Get-Content with -Path to specify file [OK]

Common Mistakes:

• Using non-existent cmdlets like Read-File
• Adding invalid parameters like -ReadAll
• Confusing parameter order

3. Given a file data.txt with these lines:
Line1
Line2
Line3
What will the command Get-Content data.txt | Select-Object -Last 1 output?

medium

A. Line1

B. Line3

C. Line2

D. Line1`nLine2`nLine3

Solution

1. Step 1: Understand Get-Content output

   Get-Content reads the file line by line, outputting each line as a separate string.

2. Step 2: Understand Select-Object -Last 1

   This selects only the last line from the input, which is "Line3".

3. Final Answer:

   Line3 -> Option B

4. Quick Check:

   Last line selected = Line3 [OK]

Hint: Select-Object -Last 1 picks last line from Get-Content output [OK]

Common Mistakes:

• Thinking it outputs all lines concatenated
• Selecting the first line instead of last
• Confusing Select-Object with filtering content

4. You run Get-Content -Path 'C:\logs\app.log' but get an error saying the file is not found. What is the most likely cause?

medium

A. PowerShell does not support reading files on C: drive

B. Get-Content cannot read .log files

C. You need to use -ReadFile instead of Get-Content

D. The file path is incorrect or the file does not exist

Solution

1. Step 1: Check file existence and path correctness

   The error usually means the file path is wrong or the file is missing at that location.

2. Step 2: Verify cmdlet capabilities and environment

   Get-Content can read any text file including .log files, and PowerShell supports reading files on C: drive.

3. Final Answer:

   The file path is incorrect or the file does not exist -> Option D

4. Quick Check:

   File not found error = wrong path or missing file [OK]

Hint: Check file path and existence first on file errors [OK]

Common Mistakes:

• Assuming Get-Content can't read .log files
• Using non-existent parameters like -ReadFile
• Thinking PowerShell can't access C: drive

5. You want to read only the first 5 lines of a large file report.txt in PowerShell. Which command will do this efficiently?

hard

A. Get-Content report.txt | Select-Object -First 5

B. Get-Content report.txt -Tail 5

C. Get-Content report.txt -First 5

D. Get-Content report.txt | Where-Object { $_ -le 5 }

Solution

1. Step 1: Understand how to select first lines

   Get-Content reads the whole file by default. To get only the first 5 lines, pipe to Select-Object -First 5.

2. Step 2: Evaluate other options

   Get-Content report.txt -Tail 5 reads last 5 lines, not first. Get-Content report.txt -First 5 is invalid syntax (no -First parameter for Get-Content). Get-Content report.txt | Where-Object { $_ -le 5 } filters lines by content, not line number.

3. Final Answer:

   Get-Content report.txt | Select-Object -First 5 -> Option A

4. Quick Check:

   Use Select-Object -First for first lines [OK]

Hint: Pipe Get-Content to Select-Object -First 5 for first lines [OK]

Common Mistakes:

• Using -Tail instead of -First
• Trying invalid -First parameter on Get-Content
• Filtering lines by content instead of line number