Solution:Step 1: Analyze casting each dictionary value'1' and '3' cast to int fine; 'two' cannot be cast to int.Step 2: Result of invalid cast in loopPowerShell throws a runtime error on casting 'two' to int, stopping execution.Final Answer:Runtime error when casting 'two' to int. -> Option DQuick C

[Solved] Given this code:$data = @{ 'a' = '1'; 'b' = 'two'; 'c' = '3' } $result = @{} foreach ($key in $data.Keys) { $result[$key] = [int]$data[$key] } Write-Output $resultWhat will happen when this runs? | PowerShell

PowerShell - Variables and Data Types

Given this code:

$data = @{ 'a' = '1'; 'b' = 'two'; 'c' = '3' }
$result = @{}
foreach ($key in $data.Keys) {
  $result[$key] = [int]$data[$key]
}
Write-Output $result

What will happen when this runs?

AValues remain strings in $result.

BAll values cast successfully; 'two' becomes 0.

CScript skips 'two' and continues.

DRuntime error when casting 'two' to int.

Step-by-Step Solution

Solution:

Step 1: Analyze casting each dictionary value
'1' and '3' cast to int fine; 'two' cannot be cast to int.
Step 2: Result of invalid cast in loop
PowerShell throws a runtime error on casting 'two' to int, stopping execution.
Final Answer:
Runtime error when casting 'two' to int. -> Option D
Quick Check:
Invalid string cast in loop = runtime error [OK]

Quick Trick: Casting invalid strings in loops causes runtime errors [OK]

Common Mistakes:

Assuming invalid casts become zero
Expecting loop to skip errors automatically
Confusing string and int types

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More PowerShell Quizzes

Given this code:

Step 1: Analyze casting each dictionary value

Step 2: Result of invalid cast in loop

Final Answer:

Quick Check:

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