[Solved] Identify the error in this PowerShell script:$number = 10 $number = $number + 5 Write-Output number — Ans: Missing $ before 'number' in Write-Output | PowerShell

PowerShell - Variables and Data Types

Identify the error in this PowerShell script:

$number = 10
$number = $number + 5
Write-Output number

ACannot add numbers in PowerShell

BVariable <code>$number</code> not declared

CMissing <code>$</code> before 'number' in Write-Output

DWrite-Output cannot print variables

Step-by-Step Solution

Solution:

Step 1: Check variable usage in Write-Output
The script tries to print 'number' without $, so it prints the word literally.
Step 2: Correct usage of variable in output
To print the variable value, it should be Write-Output $number.
Final Answer:
Missing $ before 'number' in Write-Output -> Option C
Quick Check:
Variables need $ to be recognized [OK]

Quick Trick: Always use $ before variable names when printing [OK]

Common Mistakes:

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