[Solved] Identify the error in this PHP code snippet:$json = '{"a":1, "b":2}';$arr = json_decode($json);echo $arr['a']; | PHP

PHP - File Handling

Identify the error in this PHP code snippet:

$json = '{"a":1, "b":2}';
$arr = json_decode($json);
echo $arr['a'];

Aecho cannot print array elements

BJSON string is invalid

Cjson_decode requires second argument true to work

Djson_decode returns object, not array, so use -> instead of []

Step-by-Step Solution

Solution:

Step 1: Check json_decode default return type
json_decode returns an object by default, not an array.
Step 2: Accessing object properties
Accessing with array syntax [] causes error; use -> for objects.
Final Answer:
json_decode returns object, not array, so use -> instead of [] -> Option D
Quick Check:
Access object with ->, array with [] [OK]

Quick Trick: Use -> for objects, [] for arrays after json_decode [OK]

Common Mistakes:

Master "File Handling" in PHP

9 interactive learning modes - each teaches the same concept differently

More PHP Quizzes

Identify the error in this PHP code snippet: