PHP - Type Handling
What will be the output of this PHP code?
$a = '5';
$b = 3;
echo $a + $b;
What will be the output of this PHP code?
medium📝 Predict Output Q4 of 15
Step-by-Step Solution
Solution:
Step 1: Identify variable types and operation
$a is a string '5', $b is integer 3, operation is addition (+).Step 2: Understand PHP type juggling in addition
PHP converts string '5' to integer 5, then adds 3 to get 8.Final Answer:
8 -> Option BQuick Check:
String + int = numeric addition [OK]
Quick Trick: Adding string and int converts string to number [OK]
Common Mistakes:
- Expecting string concatenation with +
- Thinking output is '53' as string concat
- Assuming error due to mixed types
Master "Type Handling" in PHP
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