[Solved] Identify the error in this PHP code:$count = 5if ($count > 3) { echo 'Count is greater than 3';} — Ans: Missing semicolon after $count = 5 | PHP

PHP - Basics and Execution Model

Identify the error in this PHP code:

$count = 5
if ($count > 3) {
  echo 'Count is greater than 3';
}

Aecho statement should be outside if block

BIncorrect if statement syntax

CMissing semicolon after $count = 5

DVariable $count is not defined

Step-by-Step Solution

Solution:

Step 1: Check variable assignment syntax
In PHP, each statement must end with a semicolon. The line $count = 5 is missing it.
Step 2: Verify if statement and echo syntax
The if statement and echo are correctly written with proper braces and syntax.
Final Answer:
Missing semicolon after $count = 5 -> Option C
Quick Check:
Statements need semicolons = A [OK]

Quick Trick: Always end PHP statements with semicolon [OK]

Common Mistakes:

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